# Find {eq}f'(x) {/eq} and {eq}f''(x) {/eq}. {eq}f\left( x \right)=\frac{x}{{{x}^{2}}-1} {/eq}

## Question:

Find {eq}f'(x) {/eq} and {eq}f''(x) {/eq}.

{eq}f\left( x \right)=\frac{x}{{{x}^{2}}-1} {/eq}

## Differentiation:

The differentiation of a function given in any form, like addition, subtraction, multiplication, division, and so on, is easy to evaluate using the differentiation rules like the sum, difference, product, and quotient rules, respectively.

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Given:

• The function is {eq}f\left( x \right) = \frac{x}{{{x^2} - 1}}{/eq}.

The objective is to find the value of {eq}f'\left( x \right){/eq}...