Find {eq}\displaystyle \dfrac {dy} {dx} {/eq} by implicit differentiation.
{eq}\displaystyle (3 x^2 - x + 2 y^3 - 1)^2 + 3 y - 2 x + 1 = 0 {/eq}
Question:
Find {eq}\displaystyle \dfrac {dy} {dx} {/eq} by implicit differentiation.
{eq}\displaystyle (3 x^2 - x + 2 y^3 - 1)^2 + 3 y - 2 x + 1 = 0 {/eq}
Implicit Differentiation:
Whether an equation is explicit or implicit, we can apply the implicit differentiation to find the derivative without even defining the dependent variable in terms of the independent variable. And we can't isolate variables in an implicit equation so, it is helpful to compute the derivative.
Answer and Explanation:
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Given Data:
- The given equation is: {eq}{\left( {3{x^2} - x + 2{y^3} - 1} \right)^2} + 3y - 2x + 1 = 0 {/eq}
Differentiate both sides of the...
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Chapter 9 / Lesson 10Learn about implicit differentiation and understand how to find the derivative of y. Explore the implicit differentiation formula with examples of how it's used.