# Find {eq}\frac{dx}{dt} {/eq} of the following function. Assume that both {eq}x {/eq} and {eq}y {/eq} are functions of {eq}t {/eq}: $$x^{2} + y^{2} = 5x$$

## Question:

Find {eq}\frac{dx}{dt} {/eq} of the following function. Assume that both {eq}x {/eq} and {eq}y {/eq} are functions of {eq}t {/eq}:

$$x^{2} + y^{2} = 5x$$

## Differentiation:

Differentiation is the method commonly used in calculus to find the derivative of the given function. This method evaluates the rate of change of the physical quantity with respect to other quantities. Differentiation finds its application in engineering, mathematics, physics, etc.

## Answer and Explanation: 1

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Given data

• The function is given as {eq}{x^2} + {y^2} = 5x {/eq}

Solution

Differentiate the given function with respect to t.

{eq}\begin{align*} ...

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