# Explain how to create a 100 mL solution of 15% NaOH by mass in water. Given the density of H2O =...

## Question:

Explain how to create a 100 mL solution of {eq}15\%\text{ }NaOH {/eq} by mass in water. Given the density of {eq}{{H}_{2}}O=1.00{g}/{c{{m}^{3}}}\; {/eq}.

## Percent by Mass

The concentration of a solution can be expressed in percent by mass. In this unit of concentration, the mass of the solute is divided by the mass of the solution and multiplied by 100. Since the solution contains a solute and a solvent, the denominator of the formula is the sum of the mass of the solute and the mass of the solvent.

{eq}\begin{aligned} Percent\;by\;mass\;&=\;\frac{mass\;solute}{mass\;solution}\;\times\;100\\ Percent\;by\;mass\;&=\;\frac{mass\;solute}{mass\;solute\;+\;mass\;solution}\;\times\;100\ \end{aligned} {/eq}

## Answer and Explanation: 1

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View this answerThe unit of concentration of the required solution is the percent by mass.

The percent by mass concentration of sodium hydroxide solution can be...

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Chapter 9 / Lesson 7What is percent composition? Learn how to find the percent composition of compounds. See how to determine the empirical formula from percent composition.