Evaluate the integral.
{eq}\int \frac{\sec \theta}{\sec \theta - \cos \theta} \, \mathrm{d} \theta {/eq}
Question:
Evaluate the integral.
{eq}\int \frac{\sec \theta}{\sec \theta - \cos \theta} \, \mathrm{d} \theta {/eq}
Indefinite Integral in Calculus:
The process of finding a function when it's derivetive is given is called anti-differentiation or integration. The symbol {eq}\int {/eq} represents integration, and {eq}dx {/eq} is a differential of the variable {eq}x {/eq} , which is a very small width of {eq}x {/eq}.
To solve this problem, we'll use apply trig-ratio {eq}\displaystyle \sec\theta= \frac{1}{ \cos \theta} {/eq}and apply trig-substitution {eq}1 - \cos^2 \theta=\sin^2 \theta {/eq}
Answer and Explanation: 1
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View this answerWe are given:
{eq}\displaystyle \int \dfrac{\sec \theta}{\sec \theta - \cos \theta} \, \mathrm{d} \theta {/eq}
Apply trig-ratio {eq}\displaystyle...
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Chapter 7 / Lesson 9Learn the work done formula and understand the application of work integral in the work done formula with examples problems using calculus.