Draw the Lewis Structure for the following element: {eq}\displaystyle \rm B {/eq}.
Question:
Draw the Lewis Structure for the following element: {eq}\displaystyle \rm B {/eq}.
Boron:
Boron is regarded to be a metalloid since it consists of metallic properties along with non-metallic properties. It can combine with several other elements to generate compounds like boranes, boron nitrides etc.
Answer and Explanation: 1
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View this answerBoron has an electronic configuration that is given as {eq}{\rm{1}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{p}}^{\rm{1}}} {/eq} ....
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Chapter 2 / Lesson 8The physical properties of boron are described in this lesson, such as density and reactivity. Learn some boron benefits and boron uses in tech applications.