Draw the Lewis Structure for the following element: {eq}\displaystyle \rm B {/eq}.

Question:

Draw the Lewis Structure for the following element: {eq}\displaystyle \rm B {/eq}.

Boron:

Boron is regarded to be a metalloid since it consists of metallic properties along with non-metallic properties. It can combine with several other elements to generate compounds like boranes, boron nitrides etc.

Answer and Explanation: 1

Become a Study.com member to unlock this answer!

View this answer

Boron has an electronic configuration that is given as {eq}{\rm{1}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{s}}^{\rm{2}}}{\rm{2}}{{\rm{p}}^{\rm{1}}} {/eq} ....

See full answer below.


Learn more about this topic:

Loading...
What is Boron? - Facts, Uses, Properties & Benefits

from

Chapter 2 / Lesson 8
16K

The physical properties of boron are described in this lesson, such as density and reactivity. Learn some boron benefits and boron uses in tech applications.


Related to this Question

Explore our homework questions and answers library