On the standardization of 10 mL of NaOH approximately 0.1 M with HCl, 9.5 mL of spent acid. Knowing that this acid was standardized with 5 mL of {eq}Na_2CO_3 {/eq} 0.05 M with 4.8 mL of it spent.
Determine the molarity of HCl used and molarity found to NaOH.
Question:
On the standardization of 10 mL of NaOH approximately 0.1 M with HCl, 9.5 mL of spent acid. Knowing that this acid was standardized with 5 mL of {eq}Na_2CO_3 {/eq} 0.05 M with 4.8 mL of it spent.
Determine the molarity of HCl used and molarity found to NaOH.
Neutralisation reaction:
Any acid capable of releasing proton in aqueous medium and any base releasing hydroxyl ion in aqueous medium, when reacted to each causes formation of a salt and a molecule of water. This reaction is called neutralisation reaction. It is an exothermic process.
Answer and Explanation: 1
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- The reaction of sodium carbonate with HCl is as follows:
{eq}Na_2CO_3 + 2HCl \to 2NaCl + H_2O + CO_2{/eq}
Molarity of sodium carbonate = 0.05 M
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Chapter 8 / Lesson 4What is molarity? What is molality? Compare molarity vs molality by viewing molality and molarity formulas, how to calculate molarity and molality, and examples.