Consider the titration of 60.0 mL of 0.10 M HBr with 0.15 M KOH. Calculate the pH after 60.0 mL...
Question:
Consider the titration of 60.0 mL of 0.10 M HBr with 0.15 M KOH. Calculate the pH after 60.0 mL of KOH has been added.
Titration and pH of a Solution:
To determine the pH value of a solution, we have to have the molar concentration of hydronium ions in the solution. If the concentration of hydroxide ions is known, then also the concentration of hydronium ions can be calculated. The following formulas are generally utilized to find the pH of a solution:
{eq}\begin{align} ~\text{ Molar concentration of a solution} &=\dfrac{~\text{ Number of moles of solute present in a solution} ~}{~\text{Volume of the solution} } \\[0.3cm] \rm p\rm{H} &= \rm -\log_{10}{[ \rm H^+]} \\ \rm p\rm{OH} &= \rm-\log_{10}{[ \rm OH^-]} \\ \rm p\rm{H} + \rm p\rm{OH}&= \rm14 \end{align} {/eq}
Answer and Explanation: 1
Become a Study.com member to unlock this answer! Create your account
View this answerWe are given:
- The concentration of the acid HBr is {eq}\rm C_1= 0.10\; \rm{M} {/eq}.
- The volume of the acid HBr is {eq}\rm V_1= 60.0 \; ...
See full answer below.
Learn more about this topic:
from
Chapter 11 / Lesson 9Learn about strong acid - strong base titration. Understand strong acid - strong base reactions and how to find an unknown substance concentration, and see the curve.