Compute {eq}\displaystyle \ \frac{\partial}{\partial y} (x^3 + y^3 +z^3 + 6xyz) = 1 {/eq}.
Question:
Compute {eq}\displaystyle \ \frac{\partial}{\partial y} (x^3 + y^3 +z^3 + 6xyz) = 1 {/eq}.
Partial Derivatives:
If a function is of several variables, then we can easily find the partial derivative with respect to given variables. Partial derivative is a derivative of one of those variable.
Answer and Explanation: 1
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View this answerGiven: {eq}\frac{\partial \left ( x^3 + y^3 +z^3 + 6xyz \right ) }{\partial y} = \frac{\partial 1}{\partial y} {/eq}
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Chapter 18 / Lesson 12What is a Partial Derivative? Learn to define first and second order partial derivatives. Learn the rules and formula for partial derivatives. See examples.