Copyright

Compute {eq}\displaystyle \ \frac{\partial}{\partial y} (x^3 + y^3 +z^3 + 6xyz) = 1 {/eq}.

Question:

Compute {eq}\displaystyle \ \frac{\partial}{\partial y} (x^3 + y^3 +z^3 + 6xyz) = 1 {/eq}.

Partial Derivatives:

If a function is of several variables, then we can easily find the partial derivative with respect to given variables. Partial derivative is a derivative of one of those variable.

Answer and Explanation: 1

Become a Study.com member to unlock this answer!

View this answer

Given: {eq}\frac{\partial \left ( x^3 + y^3 +z^3 + 6xyz \right ) }{\partial y} = \frac{\partial 1}{\partial y} {/eq}

Differentiate with respect to...

See full answer below.


Learn more about this topic:

Loading...
Partial Derivative: Definition, Rules & Examples

from

Chapter 18 / Lesson 12
24K

What is a Partial Derivative? Learn to define first and second order partial derivatives. Learn the rules and formula for partial derivatives. See examples.


Related to this Question

Explore our homework questions and answers library