# Complete and balance the following equation. If there is a precipitate or other net ionic...

## Question:

Complete and balance the following equation. If there is a precipitate or other net ionic product, write the net ionic equation.

{eq}SrCl_2(aq) + KOH(aq) \to {/eq}

## Precipitation reaction

When two or more solutions are mixed to form a precipitate is called a precipitation reaction. The reaction occurs between the ions in the aqueous solution and is affected by the temperature, pH, and concentration of the solution.

The reaction of strontium chloride with potassium hydroxide forms strontium hydroxide and potassium chloride. Strontium hydroxide will be precipitated out. The complete balanced equation is given below.

{eq}SrC{l_2}\left( {aq} \right) + 2KOH\left( {aq} \right) \to Sr{\left( {OH} \right)_2}\left( s \right) + 2KCl\left( {aq} \right) {/eq}

Converting the above equation into its ionic form.

{eq}S{r^{2 + }}\left( {aq} \right) + 2C{l^ - }\left( {aq} \right) + 2{K^ + }\left( {aq} \right) + 2O{H^ - }\left( {aq} \right) \to Sr{\left( {OH} \right)_2}\left( s \right) + 2{K^ + }\left( {aq} \right) + 2C{l^ - }\left( {aq} \right) {/eq}

The net ionic equation will be

{eq}S{r^{2 + }}\left( {aq} \right) + 2O{H^ - }\left( {aq} \right) \to Sr{\left( {OH} \right)_2}\left( s \right) {/eq}