Calculate the {eq}\left [ OH^- \right ] {/eq} of a {eq}5.5 \times 10^{-3} {/eq} M NaOH solution.
Question:
Calculate the {eq}\left [ OH^- \right ] {/eq} of a {eq}5.5 \times 10^{-3} {/eq} M NaOH solution.
Hydroxide Ion:
The hydroxide ion is a type of anion which is formed when molecules of water dissociate into ions. In the hydroxide ion, the molecules of oxygen chemical element and hydrogen chemical elements are combined with the help of one covalent bond. The chemical formula of it is {eq}\text{O}{{\text{H}}^{-}} {/eq}.
Answer and Explanation: 1
Become a Study.com member to unlock this answer! Create your account
View this answer
Given- The molarity of NaOH solution is {eq}C=5.5\times {{10}^{-3}}\ \text{M} {/eq}.
The dissociation reaction of NaOH (sodium hydroxide) solution...
See full answer below.
Learn more about this topic:
from
Chapter 28 / Lesson 44Read the hydroxide ion definition. See the hydroxide ion formula. Learn how the OH ion is formed, discover why it has a negative charge, and see examples.