Calculate the {eq}\left [ OH^- \right ] {/eq} in a 1.65 M {eq}NaOH {/eq} solution.
Question:
Calculate the {eq}\left [ OH^- \right ] {/eq} in a 1.65 M {eq}NaOH {/eq} solution.
Arrhenius base:
An important type of ionic compound pairs a group 1 or 2 metal cation with a hydroxide anion. Dissolving such a compound in water creates an aqueous solution of the constituent ions. It is termed an Arrhenius base, since its dissociation directly increases the available hydroxide ion molarity, which increases the basicity (increased pH) of a solution.
Answer and Explanation: 1
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View this answerSodium hydroxide (NaOH) is an Arrhenius base. It completely dissociates in water to provide the same hydroxide ion product molarity in solution:
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Chapter 5 / Lesson 18Learn to define Arrhenius Base. Understand the theory behind the behavior of bases, characteristics and limitations of Arrhenius bases, and see examples.