Calculate the molarity of 30.0 g of NaOH in 350 mL of NaOH solution.


Calculate the molarity of 30.0 g of NaOH in 350 mL of NaOH solution.


Molarity is used to report the concentration of a solution. The molarity of a compound is equal to the moles of the solute per liter of the solution and is typically reported in units of M or as mol/L. The solute is the species that is in less abundance than the solvent. For example, NaCl dissolved in water has a solute of NaCl and solvent of water.

Preparing Solutions:

  • Solutions are prepared in the laboratory in different ways. A solid sample can be dissolved in a solvent or liquids can be mixed with one another to prepare a solution.
  • When a mass of a solute or compound is measured, the moles should be calculated in order to determine its concentration or molarity.
  • The moles of a compound can be determined by dividing the mass of the compound measured by the molar mass of the compound.
  • The molar mass of a compound is the sum of the individual masses of each atom which can be obtained from the periodic table times the number of atoms in the compound or molecule.

Answer and Explanation: 1

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Mass NaOH = 30.0 g

volume NaOH = 350 mL = 0.350 L

First determine the moles of NaOH (molar mass = 40 g/mol)

mol NaOH {eq}= 30.0 \div 40...

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Learn more about this topic:

Calculating Molarity and Molality Concentration


Chapter 8 / Lesson 4

What is molarity? What is molality? Compare molarity vs molality by viewing molality and molarity formulas, how to calculate molarity and molality, and examples.

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