# Calculate the molarity of 30.0 g of NaOH in 350 mL of NaOH solution.

## Question:

Calculate the molarity of 30.0 g of NaOH in 350 mL of NaOH solution.

## Molarity:

Molarity is used to report the concentration of a solution. The molarity of a compound is equal to the moles of the solute per liter of the solution and is typically reported in units of M or as mol/L. The solute is the species that is in less abundance than the solvent. For example, NaCl dissolved in water has a solute of NaCl and solvent of water.

#### Preparing Solutions:

• Solutions are prepared in the laboratory in different ways. A solid sample can be dissolved in a solvent or liquids can be mixed with one another to prepare a solution.
• When a mass of a solute or compound is measured, the moles should be calculated in order to determine its concentration or molarity.
• The moles of a compound can be determined by dividing the mass of the compound measured by the molar mass of the compound.
• The molar mass of a compound is the sum of the individual masses of each atom which can be obtained from the periodic table times the number of atoms in the compound or molecule.

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Given:

Mass NaOH = 30.0 g

volume NaOH = 350 mL = 0.350 L

First determine the moles of NaOH (molar mass = 40 g/mol)

mol NaOH {eq}= 30.0 \div 40...