Calculate the molarity (M) of 158.2 g of {eq}H_2SO_4 {/eq} in 1.320 L of solution.
Question:
Calculate the molarity (M) of 158.2 g of {eq}H_2SO_4 {/eq} in 1.320 L of solution.
Molarity
Molarity is a measure of a concentration of a solution as number of moles of a solute present in the solution of 1 L volume. The formula for molarity is given below:
{eq}\rm Molarity = \dfrac{mass}{molar\, mass}\times \dfrac{1000}{volume(mL)} {/eq}
Answer and Explanation: 1
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Given :
- Mass of {eq}\rm H_2SO_4 {/eq} = {eq}158.2\ g {/eq}
- Volume of solution = {eq}1.320\ L {/eq}
- Molar mass of {eq}\rm H_2SO_4 {/eq} = {eq}98.08\...
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Calculating Molarity and Molality Concentration
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Chapter 8 / Lesson 4
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