Calculate the molarity (M) of 158.2 g of {eq}H_2SO_4 {/eq} in 1.320 L of solution.

## Question:

Calculate the molarity (M) of 158.2 g of {eq}H_2SO_4 {/eq} in 1.320 L of solution.

## Molarity

Molarity is a measure of a concentration of a solution as number of moles of a solute present in the solution of 1 L volume. The formula for molarity is given below:

{eq}\rm Molarity = \dfrac{mass}{molar\, mass}\times \dfrac{1000}{volume(mL)} {/eq}

## Answer and Explanation: 1

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Given :

- Mass of {eq}\rm H_2SO_4 {/eq} = {eq}158.2\ g {/eq}

- Volume of solution = {eq}1.320\ L {/eq}

- Molar mass of {eq}\rm H_2SO_4 {/eq} = {eq}98.08\...

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Chapter 8 / Lesson 4What is molarity? What is molality? Compare molarity vs molality by viewing molality and molarity formulas, how to calculate molarity and molality, and examples.

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