Calculate the molality of a solution prepared by dissolving 12.5 grams of NaCl in 250.0 grams of...
Question:
Calculate the molality of a solution prepared by dissolving 12.5 grams of NaCl in 250.0 grams of water. Assume the density of the final solution is 1.03 g/mL.
Molarity of a Solution:
Suppose the solute mole (n) is present in V liters of a solution; we determine the molarity using the below equation.
{eq}M\left( {{\rm{Molarity}}} \right) = \dfrac{{n\left( {{\rm{moles}}} \right)}}{{V\left( {{\rm{Liter}}} \right)}} {/eq}
The solute moles are defined using the solute mass and its molar mass.
The molarity denotes the molar concentration of a solute.
Answer and Explanation: 1
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Given Data:
- The mass of {eq}{\rm{NaCl}} {/eq} is {eq}{m_{{\rm{NaCl}}}} = 12.5\;{\rm{g}} {/eq}
- The mass of water is: {eq}m =...
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Stoichiometry: Calculating Relative Quantities in a Gas or Solution
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Chapter 9 / Lesson 4
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Learn how to find the molarity of a solution or the moles of gas in a given volume using stoichiometry. See examples of calculating moles from molarity.
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