Calculate the concentrations of all the species in a 0.391M {eq}Na_{2}CO_{3} {/eq} solution.

{eq}\left [ CO_{3}^{2-} \right ] {/eq}

{eq}\left [ HCO_{3}^{-} \right ] {/eq}

{eq}\left [ H_{2}CO_{3} \right ] {/eq}

{eq}\left [ Na^{+} \right ] {/eq}

{eq}\left [ OH^{-} \right ] {/eq}

{eq}\left [ H^{+} \right ] {/eq}

## Question:

Calculate the concentrations of all the species in a 0.391M {eq}Na_{2}CO_{3} {/eq} solution.

{eq}\left [ CO_{3}^{2-} \right ] {/eq}

{eq}\left [ HCO_{3}^{-} \right ] {/eq}

{eq}\left [ H_{2}CO_{3} \right ] {/eq}

{eq}\left [ Na^{+} \right ] {/eq}

{eq}\left [ OH^{-} \right ] {/eq}

{eq}\left [ H^{+} \right ] {/eq}

## Hydrolysis

Hydrolysis is a chemical reaction of double decomposition type reaction with water as one of the reactants. This can be represented using the chemical equation

{eq}AB + HOH \rightleftharpoons AH + BOH {/eq}

## Answer and Explanation: 1

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View this answerCarbonate ion {eq}CO_3^{2-} {/eq} is a weak base that will produce equal amounts of {eq}HCO_3^- {/eq} and {eq}OH^- {/eq} in water.

Dissociation

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Chapter 24 / Lesson 7Learn about salt hydrolysis. Read the definition of salt hydrolysis, examples of salt hydrolysis, and how to determine the pH of salts including the formula.