Between each pair of vertebrae in the spinal column is a cylindrical disc of cartilage....
Question:
Between each pair of vertebrae in the spinal column is a cylindrical disc of cartilage. Typically, this disc has a radius of about 2.82*10{eq}^{-2} {/eq} m and a thickness of about 7.07*10{eq}^{-3} {/eq} m. The shear modulus of cartilage is 1.18*10{eq}^7 N/m^2 {/eq}. Suppose that a shearing force of magnitude 10 N is applied parallel to the top surface of the disc while the bottom surface remains fixed in place. How far does the top surface move relative to the bottom surface?
Shear Modulus:
Shear modulus or the modulus of rigidity of a material is defined by the ratio of the shear stress {eq}(\tau ) {/eq} to the shear strain acting {eq}(\gamma) {/eq} on the material.
{eq}\displaystyle G =\frac{\tau }{\gamma} {/eq}
Answer and Explanation: 1
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- The shearing force acting on the disk between vertebrae in the spine is {eq}F _s =10 \ N {/eq}.
- The disk is equivalent to a solid cylinder of...
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Chapter 2 / Lesson 10Explore shear strain in physics. Learn the definition of shear strain and understand the shear strain formula. Discover various examples of shear strain.
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