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After you add 0.009 grams of NaCl to 150 mL of water, you find that you are still able to add...

Question:

After you add 0.009 grams of NaCl to 150 mL of water, you find that you are still able to add 0.250 grams more of NaCl to that solution and it completely dissolves. How would you describe the original solution formed from the 0.009 grams of NaCl in the 150 mL of water?

a. The original solution was saturated.

b. The original solution was unsaturated.

c. The original solution was supersaturated.

d. The original solution was not soluble.

Solubility:

The dissolution of a solute in a solvent eventually reaches an equilibrium wherein the rate of dissolution and rate of recrystallization are equal to one another. This is the definition of a saturated solution wherein the undissolved solute (solid) is in equilibrium with the dissolved ions. No more solute will dissolve in the solvent when the solution is saturated. If more solute is added, the concentration of the solute in the solution ceases to increase.

Answer and Explanation: 1

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Since more NaCl can be dissolved, we can describe that b. The original solution was unsaturated.

An unsaturated solution contains less than the...

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Solubility and Solubility Curves

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Chapter 8 / Lesson 3
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This lesson discusses what a solubility curve is, how to read it, what the units are, and the definitions of saturated, unsaturated, and supersaturated solutions.


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