a. {eq}y = \frac{\tan x \sec x}{1 - \cos x} {/eq}, find y'.
b. {eq}f(t) = \sqrt{t^3 + 2 \cos t}, {/eq} find f'(0).
Question:
a. {eq}y = \frac{\tan x \sec x}{1 - \cos x} {/eq}, find y'.
b. {eq}f(t) = \sqrt{t^3 + 2 \cos t}, {/eq} find f'(0).
Derivatives:
In order to solve the given problem on derivatives, we will apply the basic rules and standard formulae of the differential calculus. In the first part, we will apply the "product rule" of the differential calculus. {eq}\begin{align*} \frac{d}{dx}(u \cdot v) = (u \cdot v' + v \cdot u') \end{align*} {/eq}.
Answer and Explanation: 1
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a. {eq}y = \frac{\tan x \sec x}{1 - \cos x} {/eq}. Find y'.
Differentiating the above by applying "product rule", we get:
{eq}\begin{al...
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Chapter 8 / Lesson 13The rules of differentiation are useful to find solutions to standard differential equations. Identify the application of product rule, quotient rule, and chain rule to solving these equations through examples.