A solution was prepared by dissolving 1 gram of NH3 in 250 grams of water. The density of the...
Question:
A solution was prepared by dissolving 1 gram of {eq}NH_3 {/eq} in 250 grams of water. The density of the resulting solution was 0.974 g/mL. Determine the mole fraction of {eq}NH_3 {/eq} in the solution.
Mole fraction:
Mole fraction is the fraction of a chemical species in a mixture in terms of moles. It can be used to determine the partial pressure of the gas in a mixture. It can also be used to determine the pressure of a system given the mole fractions of the components with their respective vapor pressure at pure state.
Answer and Explanation: 1
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View this answerTo calculated for the mole fraction, the amounts should be first converted to the moles.
{eq}\rm{} mole\ NH_3 = (1\ g)(\dfrac{1\ mol}{17.031\ g}) =...
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