A solution contains 1.41 x 10-2 M potassium sulfite and 1.50 x 10-2 M sodium chromate. Solid...
Question:
A solution contains {eq}1.41 \times 10^{-2} {/eq} M potassium sulfite and {eq}1.50 \times 10^{-2} {/eq} M sodium chromate. Solid silver nitrate is added slowly to this mixture.
a. What is the formula of the substance that precipitates first?
b. What is the concentration of silver ion when this precipitation first begins?
Selective Precipitation:
An insoluble salt compound can be created as a product in a precipitation reaction system. One possible set up involves adding a solid salt compound to an aqueous solution of a different salt compound, in which these two compounds contain certain constituent ions that will pair up to form the insoluble product. The product will precipitate when the solubility product of its constituent ion molarity values exceeds its {eq}\rm K_{sp} {/eq} value. In selective precipitation the added salt compound contains a common ion that will form multiple different insoluble salt compound products in the resulting solution. Therefore, these products share a certain constituent ion. Their {eq}\rm K_{sp} {/eq} values are usually different enough that the products will begin to precipitate at different times.
Answer and Explanation: 1
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This question involves selective precipitation of sulfite and chromate anions. They are provided by complete dissociation of {eq}\rm...
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Chapter 11 / Lesson 6Learn about the common ion effect on solubility. Learn what a common ion is, examine a common ion chart, and work through examples of the common ion effect.
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