A point source of a wave emits 195 watts. What is the intensity at a distance of 4.56 meters?
Question:
A point source of a wave emits 195 watts. What is the intensity at a distance of 4.56 meters?
Wave Intensity
The intensity of a wave can be identified by dividing the power and the area covered. So mathematically we can obtain the intensity by this equation,
$$I = \dfrac{P}{A} $$
whereas P is the power which is the rate of energy being transported by the wave and A is the area which is equal to {eq}A = 4\pi r^2 {/eq}. So, in conclusion, our equation will be,
$$I = \dfrac{P}{4\pi r^2} $$
Answer and Explanation: 1
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The given quantities that we have:
- The power output of the wave is {eq}P = 195\ Watts {/eq}
- At a distance of {eq}r = 4.56\ m {/eq}
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Intensity in Physics: Definition & Measurement
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Chapter 5 / Lesson 10
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This lesson explains what wave intensity in physics is, and it explains the intensity of light formula with examples. This lesson also describes how to calculate intensity of sound waves.
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