# A point source of a wave emits 195 watts. What is the intensity at a distance of 4.56 meters?

## Question:

A point source of a wave emits 195 watts. What is the intensity at a distance of 4.56 meters?

## Wave Intensity

The intensity of a wave can be identified by dividing the power and the area covered. So mathematically we can obtain the intensity by this equation,

$$I = \dfrac{P}{A}$$

whereas P is the power which is the rate of energy being transported by the wave and A is the area which is equal to {eq}A = 4\pi r^2 {/eq}. So, in conclusion, our equation will be,

$$I = \dfrac{P}{4\pi r^2}$$

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The given quantities that we have:

• The power output of the wave is {eq}P = 195\ Watts {/eq}
• At a distance of {eq}r = 4.56\ m {/eq}

We are...