# A point source of a wave emits 195 watts. What is the intensity at a distance of 4.56 meters?

## Question:

A point source of a wave emits 195 watts. What is the intensity at a distance of 4.56 meters?

## Wave Intensity

The intensity of a wave can be identified by dividing the power and the area covered. So mathematically we can obtain the intensity by this equation,

$$I = \dfrac{P}{A} $$

whereas *P* is the power which is the rate of energy being transported by the wave and *A* is the area which is equal to {eq}A = 4\pi r^2
{/eq}. So, in conclusion, our equation will be,

$$I = \dfrac{P}{4\pi r^2} $$

## Answer and Explanation: 1

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The given quantities that we have:

- The power output of the wave is {eq}P = 195\ Watts {/eq}

- At a distance of {eq}r = 4.56\ m {/eq}

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Chapter 5 / Lesson 10This lesson explains what wave intensity in physics is, and it explains the intensity of light formula with examples. This lesson also describes how to calculate intensity of sound waves.

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