(a) Find the speed of a satellite moving around the earth in a circular orbit that has a radius...
Question:
(a) Find the speed of a satellite moving around the earth in a circular orbit that has a radius equal to four times the earth's radius of {eq}6.38 \times 10^{6} {/eq} m.
(b) Find the satellite's orbital period.
Gravitational Force:
The gravitational force is the interaction force between two bodies with masses. This force is directly proportional to the product of the {eq}m_{1} {/eq} (mass of the body 1) and {eq}m_{2} {/eq} (mass of the body 2). It's inversely proportional to the squared of the distance between them {eq}r {/eq}:
$$\begin{align} Fg = G\frac{m_{1}m_{2}}{r^{2}} \end{align} $$
This force is responsible for the days and nights, as the earth moves around the sun in a circular path due to the action of this force.
Answer and Explanation: 1
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- {eq}r = 4~R = 4\times 6.38~\times 10^{6}~m = 25.5 \times 10^{6}~m {/eq} satellite circular orbit radius
- {eq}M_{e} = 5.97 \times...
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