A faint sound with an intensity of 10^{-9}\ \mathrm{W/m^2} is measured by an intensity-level...
Question:
A faint sound with an intensity of {eq}10^{-9}\ \mathrm{W/m^2} {/eq} is measured by an intensity-level meter. What will the reading be in {eq}\mathrm{dB} {/eq}?
Sound Intensity:
First we need to understand the sound intensity to solve this problem. Suppose {eq}I {/eq} is the sound intensity level in watt per meter and {eq}I_0 {/eq} is a reference intensity, then the sound intensity level in decibels is expressed as: {eq}\displaystyle dB = 10 \log \frac{I}{I_0} {/eq} where {eq}I_0 = 10^{- 12} \ \rm W / m^2 {/eq}.
Answer and Explanation: 1
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Given:
- The sound intensity is: {eq}I = 10^{- 3} \ \rm W / m^2 {/eq}.
We will compute the sound intensity in decibels. As we know the formula for...
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Intensity in Physics: Definition & Measurement
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Chapter 5 / Lesson 10
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This lesson explains what wave intensity in physics is, and it explains the intensity of light formula with examples. This lesson also describes how to calculate intensity of sound waves.
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