# A faint sound with an intensity of 10^{-9}\ \mathrm{W/m^2} is measured by an intensity-level...

## Question:

A faint sound with an intensity of {eq}10^{-9}\ \mathrm{W/m^2} {/eq} is measured by an intensity-level meter. What will the reading be in {eq}\mathrm{dB} {/eq}?

## Sound Intensity:

First we need to understand the sound intensity to solve this problem. Suppose {eq}I {/eq} is the sound intensity level in watt per meter and {eq}I_0 {/eq} is a reference intensity, then the sound intensity level in decibels is expressed as: {eq}\displaystyle dB = 10 \log \frac{I}{I_0} {/eq} where {eq}I_0 = 10^{- 12} \ \rm W / m^2 {/eq}.

## Answer and Explanation: 1

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Given:

- The sound intensity is: {eq}I = 10^{- 3} \ \rm W / m^2 {/eq}.

We will compute the sound intensity in decibels. As we know the formula for...

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Chapter 5 / Lesson 10This lesson explains what wave intensity in physics is, and it explains the intensity of light formula with examples. This lesson also describes how to calculate intensity of sound waves.

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