A clock reaction is run at 20°C with several different mixtures of iodide, sodium bromate and...

Question:

A clock reaction is run at 20°C with several different mixtures of iodide, sodium bromate and acid, to form iodine. Thiosulfate is used to react with the iodine formed initially. Starch indicator is added to form a blue color when all the thiosulfate has been used up and the iodine concentration begins to rise. Mixtures with the following initial concentrations are used:

Run number [I-] [BrO3-][H+]
10.0020.0080.02
20.0020.0160.02
30.0040.0080.02
40.0020.0080.04

[S2O32- ] is equal to 0.0001M in each reaction mixture. The rate law is Rate = {eq}k [I^-]^a[BrO_3^-]^b[H^+]^c {/eq}. The reaction time is 30 s in run 1, 30 s in run 2, 15 s in run 3, and 30 s in run 4. Calculate a, b, and c in the rate law.

Clock Reaction:

A clock reaction is a chemical reaction that can be used as a clock, meaning that the reaction can be used to measure time. That is possible because the observable changes of the reaction happen after a period of time that can be predicted relatively easily.

Answer and Explanation: 1

Become a Study.com member to unlock this answer!

View this answer

The order of the reaction for each chemical species is calculated by comparing the rate of the reaction for two runs and the concentrations of the...

See full answer below.


Learn more about this topic:

Loading...
Rate of a Chemical Reaction: Modifying Factors

from

Chapter 12 / Lesson 1
46K

Learn about the rate of reaction. Understand the factors affecting the rate of reaction and see how catalyst, concentration, temperature and surface area affect it.


Related to this Question

Explore our homework questions and answers library