A clock reaction is run at 20°C with several different mixtures of iodide, sodium bromate and...
Question:
A clock reaction is run at 20°C with several different mixtures of iodide, sodium bromate and acid, to form iodine. Thiosulfate is used to react with the iodine formed initially. Starch indicator is added to form a blue color when all the thiosulfate has been used up and the iodine concentration begins to rise. Mixtures with the following initial concentrations are used:
Run number | [I-] | [BrO3-] | [H+] |
---|---|---|---|
1 | 0.002 | 0.008 | 0.02 |
2 | 0.002 | 0.016 | 0.02 |
3 | 0.004 | 0.008 | 0.02 |
4 | 0.002 | 0.008 | 0.04 |
[S2O32- ] is equal to 0.0001M in each reaction mixture. The rate law is Rate = {eq}k [I^-]^a[BrO_3^-]^b[H^+]^c {/eq}. The reaction time is 30 s in run 1, 30 s in run 2, 15 s in run 3, and 30 s in run 4. Calculate a, b, and c in the rate law.
Clock Reaction:
A clock reaction is a chemical reaction that can be used as a clock, meaning that the reaction can be used to measure time. That is possible because the observable changes of the reaction happen after a period of time that can be predicted relatively easily.
Answer and Explanation: 1
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View this answerThe order of the reaction for each chemical species is calculated by comparing the rate of the reaction for two runs and the concentrations of the...
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Chapter 12 / Lesson 1Learn about the rate of reaction. Understand the factors affecting the rate of reaction and see how catalyst, concentration, temperature and surface area affect it.
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