A child pushes a merry-go-round from rest to a final angular speed of 0.6 rev/s with constant...
Question:
A child pushes a merry-go-round from rest to a final angular speed of 0.6 rev/s with constant angular acceleration. In doing so, the child pushes the merry-go-round 1.8 revolutions. What is the angular acceleration of the merry-go-round? rad/s{eq}^2 {/eq}
Rotational Motion
A rotating body is said to be having a rotational motion when it rotates a constant angular velocity or acceleration. The motion can be presented by angular variables using the known four kinematic equations.
Answer and Explanation: 1
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View this answerConsider solving the angular acceleration using
{eq}2\alpha\theta = \omega_f^2 - \omega_i^2 {/eq}
where
- {eq}\alpha {/eq} is the angular...
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Physics students should be comfortable applying rotational motion formulas. Review the definition of rotational motion and practice using the relevant formulas with the provided examples.
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