A 84.5-kg person stands on a scale in an elevator. What is the apparent weight when the elevator...
Question:
A 84.5-kg person stands on a scale in an elevator. What is the apparent weight when the elevator is (a) accelerating upward with an acceleration of 1.93 m per s{eq}^2 {/eq}, (b) moving upward at a constant speed, and (c) accelerating downward with an acceleration of 1.57 m per s{eq}^2 {/eq}?
Newton's Laws of Motion
According to Newton's Laws of motion, a net external force acting on a particle of mass {eq}m {/eq} results in its acceleration, given by:
{eq}F \ = \ m \times a {/eq}
As a consequence, for the body to remain at rest (translational equilibrium), total external fore acting on the body must be zero i.e.
{eq}\Sigma \ F_i \ = \ F \ = \ 0 \ {/eq}
Answer and Explanation: 1
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- Mass of the person: {eq}M \ = \ 84.5 \ kg {/eq}
a. When the elevator is accelerating upwards: {eq}a \ = \ 1.93 \ ms^{-2} {/eq}
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Newton's Laws of Motion | Overview & Examples
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Chapter 3 / Lesson 6
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Learn about Sir Isaac Newton's laws of motion. Get an overview of each of Newton's three laws, see how they are related to each other, and get examples of each.
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