# A 25.0 mL solution of 0.0460 M EDTA was added to a 49.0 mL sample containing an unknown...

## Question:

A {eq}25.0 \ mL {/eq} solution of {eq}0.0460 \ M \ EDTA {/eq} was added to a {eq}49.0 \ mL {/eq} sample containing an unknown concentration of {eq}V^{3+} {/eq}. All {eq}V^{3+} {/eq} present formed a complex, leaving excess {eq}EDTA {/eq} in solution. This solution was back-titrated with a {eq}0.0490 \ M \ Ga^{3+} {/eq} solution until all the {eq}EDTA {/eq} reacted, requiring {eq}10.0 \ mL {/eq} of the {eq}Ga^{3+} {/eq} solution. What was the original concentration of the {eq}V^{3+} {/eq} solution?

## Back Titration:

Complexometric titration involves complexing agents like EDTA. There are different types of EDTA titrations. In case of a back titration, an additional amount of EDTA is added to the solution. After the reaction, this additional EDTA is then titrated with another solution with a known concentration.

## Answer and Explanation: 1

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View this answer**Given Data**

- The volume of EDTA solution is 25.0 mL.
- The molarity of EDTA solution is 0.0460 M.
- The volume of {eq}{{\rm{V}}^{3 + }} {/eq} solution is...

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Chapter 24 / Lesson 7Learn about the titration equation and its uses in titration calculations. Find titration calculation examples covering how to calculate molarity from titration.

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