A 17 mL solution of 15 mM sodium iodate is titrated by precipitation with 10 mM lead (II) acetate...
Question:
A 17 mL solution of 15 mM sodium iodate is titrated by precipitation with 10 mM lead (II) acetate ({eq}Pb(CH_3CO_2)_2 {/eq}). Determine the concentrations of lead and iodate free in solution at each titration volume listed below.
a) 5 mL before the equivalence point
b) At the equivalence point
c) 6 mL past the equivalence point
Precipitation Reaction:
The formation of a stable solid compound in the final solution when the two or more aqueous ionic compounds are mixed together is known as the precipitation reaction. It is also known as ion exchange reaction.
Answer and Explanation: 1
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View this answerWe are given:
- Molarity of {eq}\rm NaIO_3 = 15\ mM {/eq}
- Volume of {eq}\rm NaIO_3 = 17\ mL {/eq}
- Molarity of {eq}\rm Pb(CH_3CO_2)_2 = 10\ mM {/eq}
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Chapter 19 / Lesson 8What is precipitation? Learn the definition, formation, types, and examples of precipitation. Also, learn the meaning of the term precipitate.
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