A 13 g bullet traveling 330 m/s penetrates a 2.0 kg Block of wood and emerges going 270 m/s . If...

Question:

A {eq}13\ g {/eq} bullet traveling {eq}330\ \rm m/s {/eq} penetrates a {eq}2.0\ kg {/eq} Block of wood and emerges going {eq}270\ \rm m/s {/eq} . If the block is stationary on a frictionless surface when hit how fast does it move after the bullet emerges?

Conservation of Momentum:

Momentum is the product of mass and velocity. After a collision, the law of conservation of momentum states that the total initial momentum and the total final momentum must be the same.

Answer and Explanation: 1

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By conservation of momentum, the initial and final momenta of the block and bullet must be the same:

{eq}m_b v_{bi} + m_w v_{wi} = m_b v_{bf} + m_w...

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Law of Conservation of Momentum | Overview & Formula

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Chapter 13 / Lesson 2
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Learn about the law of conservation of momentum. Understand the basic principle, the equation of conservation of linear momentum, and its application with examples.


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