85ml of 0.1M H_2SO_4 solution is titrated against 0.1N KOH solution. Calculate the concentration...


85 mL of 0.10 M {eq}\rm H_2SO_4 {/eq} solution is titrated against 0.10 N KOH solution. Calculate the concentration of salt formed when the acid is one fourth neutralized.

Neutralization Reaction:

A neutralization reaction is when an acid and base are mixed in chemically equivalent quantities to reach the required equivalence point. For a diprotic acid titrated with a Group 1 alkali metal hydroxide base, this will require a 1:2 molar ratio to reach the equivalence point. This neutralization reaction will form water and a salt as products.

Answer and Explanation: 1

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This neutralization reaction will produce potassium sulfate as a salt:

{eq}\rm H_2SO_4 (aq) + 2KOH (aq) \rightarrow 2H_2O (l) + K_2SO_4 (aq) {/eq}

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Neutralization and Acid-Base Reactions


Chapter 10 / Lesson 5

Learn about acid-base neutralization reactions. Understand the reaction between acid and base, the neutralization reaction, the definition, and see the products.

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