# 350 mL of 0.25 M KOH is reacted with 250 mL of 0.30 M H3PO4. Determine which is the limiting...

## Question:

350 mL of 0.25 M KOH is reacted with 250 mL of 0.30 M H{eq}_3 {/eq}PO{eq}_4 {/eq}. Determine which is the limiting reagent, the molarity of the salt formed, and the final molarity of the reactant that was in excess.

## Limiting Reagent:

Limiting reagent can be assessed by the division of calculated moles of components by their stoichiometric coefficients. The amount of which component is less, then it is termed as limiting reagent.

## Answer and Explanation: 1

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**Given Data:**

- The volume of KOH is 350 mL.
- The molarity of KOH is 0.25 M.
- The molarity of {eq}{{\rm{H}}_{\rm{3}}}{\rm{P}}{{\rm{O}}_{\rm{4}}} {/eq}...

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Chapter 9 / Lesson 7Learn the definition of a limiting reactant, the formula, and how to determine a limiting reactant. See examples of limiting reactants and their problems.

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