# 1. Write a net ionic equation for the reaction that occurs when aqueous solutions of hydrobromic...

## Question:

1. Write a net ionic equation for the reaction that occurs when aqueous solutions of hydrobromic acid and sodium hydroxide are combined.

2. Write a net ionic equation for the reaction that occurs when aqueous solutions of hydrobromic acid and potassium hydroxide are combined.

3. Consider the reaction when aqueous solutions of ammonium phosphate and calcium iodide are combined. What is the net ionic equation for this reaction?

4. Consider the reaction when aqueous solutions of sodium hydroxide and copper(II) acetate are combined. What is the net ionic equation for this reaction?

## Net Ionic Equations

Ions in solution must always have a counter ion. This means to add a desired ion to a solution the counter ion must also be added. The counter ion should be chosen so that it does not participate in the reaction. In this sense the counter ion would be a spectator for the reaction and called a spectator ion. A reaction equation includes every element that is present for the reaction in order to account for everything. However, a net ionic equation does not include the spectator ions and just focuses on the ions that are participating in the reaction.

1. The reaction equation would be {eq}HBr + NaOH \rightarrow H_2O + NaBr {/eq}

NaBr is soluble in water which means that Na and Br ions started and ended as aqueous ions. This makes them spectator ions. The net ionic equation is {eq}H^+ + OH^- \rightarrow H_2O {/eq}

2. The reaction equation would be {eq}HBr + KOH \rightarrow H_2O + KBr {/eq}

NaBr is soluble in water which means that K and Br ions started and ended as aqueous ions. This makes them spectator ions. The net ionic equation is {eq}H^+ + OH^- \rightarrow H_2O {/eq}

3. The reaction equation would be {eq}2(NH_4)_3PO_4 + 3CaI_2 \rightarrow 6NH_4I + Ca_3(PO_4)_2 {/eq}

Ammonium iodide is soluble in water which means that ammonium and iodide ions started and ended as aqueous ions. This makes them spectator ions. The net ionic equation is {eq}3Ca^{+2} + 2PO_4^{-3} \rightarrow Ca_3(PO_4)_2 {/eq}

4. The reaction equation would be {eq}2NaOH + Cu(C_2H_8O_2)_2 \rightarrow 2NaC_2H_8O_2 + Cu(OH)_2 {/eq}

Sodium acetate is soluble in water which means that sodium and acetate ions started and ended as aqueous ions. This makes them spectator ions. The net ionic equation is {eq}Cu^{+2} + 2OH^- \rightarrow Cu(OH)_2 {/eq}