1.) How many grams of oxygen gas , O2, are produced when 65.5 grams of sodium chlorate, NaClO3,...
Question:
1.) How many grams of oxygen gas , O2, are produced when 65.5 grams of sodium chlorate, NaClO3, decomposes in the following reaction using mole ratio.
2NaClO3 (s) --> 2NaCl (s) + 3O2 (g)
2.) How many grams of ethanol , C2H5OH, are produced to react with 100 grams of oxygen gas, O2, in the following reaction using mole ratio.
C2H5OH + 3O2 --> 2CO2 + 3H2O
Stoichiometry
We are given 2 balanced reactions. These balanced reactions can be used to convert from moles of one species in the reaction to moles of another by using the stoichiometric ratio described by the reaction. In the two problems given, we can determine the answer in a three step calculation: 1) use the molar mass of the species given to convert from grams to moles, 2) use the stoichiometric ratio to convert from moles o the given species to moles of the species of interest, and 3) use the molar mass of the species of interest to convert from moles to the mass of the species of interest.
Answer and Explanation: 1
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View this answerPart A: The molar mass of sodium chlorate is 106g/mol. The molar mass of oxygen is 32g/mol.
{eq}65.5g \cdot \frac{1mol}{106g} \cdot...
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